Chemistry | Class 12 | NCERT Comprehensive Edition
HALOALKANES & HALOARENES
Every concept. Every mechanism. Every reaction. Decoded.
0. Overview
📐 FORMULA CHEAT SHEET – MUST MEMORIZE
PART 1 – INTRODUCTION & CLASSIFICATION
Board Weightage: ★★★☆☆What are Haloalkanes?
- Haloalkanes (also called alkyl halides) are organic compounds containing a carbon-halogen (C-X) bond
- The halogen atom (X) can be fluorine (F), chlorine (Cl), bromine (Br), or iodine (I)
- General formula: CₙH₂ₙ₊₁X for monohaloalkanes
- Example: CH₃Cl (chloromethane), C₂H₅Br (bromoethane)
What are Haloarenes?
- Haloarenes (also called aryl halides) have the halogen atom directly attached to an aromatic ring
- The halogen is bonded to an sp² hybridized carbon of the benzene ring
- Example: C₆H₅Cl (chlorobenzene), C₆H₅Br (bromobenzene)
Functional Group
- Functional group: -X (halogen atom)
- The halogen is the characteristic functional group in both haloalkanes and haloarenes
General Formula
- Monohaloalkanes: CₙH₂ₙ₊₁X
- Dihaloalkanes: CₙH₂ₙX₂
- Trihaloalkanes: CₙH₂ₙ₋₁X₃
- Polyhaloalkanes: CₙH₂ₙ₊₁₋ₓXₓ
Classification of Haloalkanes
Based on Number of Halogen Atoms
Monohaloalkanes
Contain one halogen atom
Example: CH₃CH₂Cl (chloroethane)
Dihaloalkanes
Contain two halogen atoms
Geminal: CH₂Cl₂ (both on same carbon)
Vicinal: CH₂ClCH₂Cl (adjacent carbons)
Trihaloalkanes
Contain three halogen atoms
Example: CHCl₃ (chloroform)
Polyhaloalkanes
Contain four or more halogen atoms
Example: CCl₄ (carbon tetrachloride)
Based on Carbon Atom Bearing Halogen
Primary (1°) Haloalkanes
Halogen attached to a primary carbon
Example: CH₃CH₂Cl (1-chloroethane)
Secondary (2°) Haloalkanes
Halogen attached to a secondary carbon
Example: CH₃CHClCH₃ (2-chloropropane)
Tertiary (3°) Haloalkanes
Halogen attached to a tertiary carbon
Example: (CH₃)₃CCl (2-chloro-2-methylpropane)
Classification of Haloarenes
- Classified based on the position of halogen on the benzene ring
- Ortho: Halogens at positions 1 and 2
- Meta: Halogens at positions 1 and 3
- Para: Halogens at positions 1 and 4
- CH₃CH₂Cl – primary chloride
- (CH₃)₂CHBr – secondary bromide
- (CH₃)₃CCl – tertiary chloride
NOMENCLATURE (IUPAC)
Board Weightage: ★★★★☆Rules for Haloalkanes
- Select the longest continuous carbon chain containing the halogen
- Number the chain to give the halogen the lowest possible number
- Name the halogen as a prefix: fluoro, chloro, bromo, iodo
- For multiple halogens, use prefixes: di-, tri-, tetra-
- List substituents alphabetically (ignoring prefixes like di-, tri-)
Examples
| Formula | IUPAC Name | Common Name |
|---|---|---|
| CH₃CH₂Cl | Chloroethane | Ethyl chloride |
| CH₃CHClCH₃ | 2-Chloropropane | Isopropyl chloride |
| CH₂ClCH₂Cl | 1,2-Dichloroethane | Ethylene dichloride |
| CH₃CH(Br)CH₂Cl | 2-Bromo-1-chloropropane | - |
Board Naming Questions
Answer: 1-Chloropropane
Q2. Write the IUPAC name of CH₃CHClCH₂CH₃
Answer: 2-Chlorobutane
Q3. Write the IUPAC name of CH₃CH(Br)CH₃
Answer: 2-Bromopropane
No reactions to memorize in this section
- Only structures, classification, and nomenclature
- Focus on identifying 1°, 2°, 3° haloalkanes
- Practice IUPAC naming
PART 2 – PREPARATION OF HALOALKANES FROM ALCOHOLS
Board Weightage: ★★★★★1. Reaction with HX (Hydrogen Halides)
Conditions:
- HCl, HBr, or HI
- Anhydrous ZnCl₂ (Lucas Reagent) for HCl
- Conc. H₂SO₄ for HBr and HI
Lucas Test
- Lucas Reagent: Conc. HCl + ZnCl₂
- Used to distinguish between 1°, 2°, and 3° alcohols
- 3° alcohols: Immediate turbidity (forms alkyl halide, immiscible)
- 2° alcohols: Turbidity within 5 minutes
- 1° alcohols: No turbidity at room temperature
Mechanism:
- 3° alcohols: SN1 mechanism (carbocation formation)
- 1° and 2° alcohols: SN2 mechanism
- CH₃CH₂OH + HCl/ZnCl₂ → CH₃CH₂Cl + H₂O
- (CH₃)₃COH + HCl/ZnCl₂ → (CH₃)₃CCl + H₂O
2. Reaction with SOCl₂ (Thionyl Chloride)
Conditions:
- Anhydrous conditions
- Pyridine can be used as base
- Gaseous byproducts (SO₂ and HCl) escape
- Pure product obtained
- No rearrangement
3. Reaction with PCl₃ (Phosphorus Trichloride)
Conditions:
- Heat
- Anhydrous conditions
4. Reaction with PCl₅ (Phosphorus Pentachloride)
Conditions:
- Heat
- Anhydrous conditions
5. Reaction with PBr₃ (Phosphorus Tribromide)
Conditions:
- Heat
- Anhydrous conditions
6. Reaction with PI₃ (Phosphorus Triiodide)
- ROH + HCl/ZnCl₂ → RCl + H₂O (Lucas Reagent)
- ROH + SOCl₂ → RCl + SO₂ + HCl (Thionyl chloride)
- 3ROH + PCl₃ → 3RCl + H₃PO₃
- ROH + PCl₅ → RCl + POCl₃ + HCl
- 3ROH + PBr₃ → 3RBr + H₃PO₃
- 3ROH + PI₃ → 3RI + H₃PO₃
PART 2 (CONTINUED) – PREPARATION FROM ALKANES (FREE RADICAL HALOGENATION)
Board Weightage: ★★★★★ (Extremely Important)General Reaction
Where: RH = Alkane, X₂ = Cl₂ or Br₂, RX = Haloalkane, HX = HCl or HBr
Why is Sunlight Required?
- Sunlight (hν) or heat (Δ) provides energy to break the X-X bond
- This bond breaks homolytically (each atom gets one electron)
- Free radicals are formed: Cl• or Br•
What is a Free Radical?
- A neutral species containing an unpaired electron
- Highly reactive because it tries to pair its unpaired electron
- Examples: Cl•, CH₃•, Br•
Mechanism of Free Radical Halogenation
- I = Initiation
- P = Propagation
- T = Termination
Stage 1 – Initiation
Reaction: Cl₂ ──hν──► Cl• + Cl•
This is called homolytic cleavage
Stage 2 – Propagation
Step 1: Cl• + CH₄ ──► CH₃• + HCl
Chlorine radical removes one hydrogen atom. Methane becomes a methyl radical.
Step 2: CH₃• + Cl₂ ──► CH₃Cl + Cl•
Product: Chloromethane. A new chlorine radical is formed.
Stage 3 – Termination
Reactions:
- Cl• + Cl• ──► Cl₂
- CH₃• + Cl• ──► CH₃Cl
- CH₃• + CH₃• ──► C₂H₆ (Ethane is formed)
Chlorination of Methane
CH₄ ↓ CH₃Cl (Chloromethane) ↓ CH₂Cl₂ (Dichloromethane) ↓ CHCl₃ (Trichloromethane/Chloroform) ↓ CCl₄ (Tetrachloromethane)
Reactions:
- CH₄ + Cl₂ ──hν──► CH₃Cl + HCl
- CH₃Cl + Cl₂ ──hν──► CH₂Cl₂ + HCl
- CH₂Cl₂ + Cl₂ ──hν──► CHCl₃ + HCl
- CHCl₃ + Cl₂ ──hν──► CCl₄ + HCl
Bromination of Alkanes
Chlorination vs Bromination
| Feature | Chlorination | Bromination |
|---|---|---|
| Speed | Faster | Slower |
| Selectivity | Less selective | More selective |
| Products | Mixture of products | Major product predominates |
| Control | Less controlled | Better controlled |
Why is Bromination More Selective?
- Bromination has a higher activation energy
- Therefore, it reacts mainly with the most stable free radical
- Major product predominates
- Chlorination reacts rapidly and forms many products
Stability of Free Radicals
3° > 2° > 1° > CH₃•
Reason: Alkyl groups donate electrons by the +I (inductive) effect and hyperconjugation, stabilizing the free radical.
Mnemonic: 3 > 2 > 1 > M (Methyl)
Example: Monochlorination of Propane
Possible Products:
- 1-Chloropropane: CH₃CH₂CH₂Cl (Primary)
- 2-Chloropropane: CH₃CHClCH₃ (Secondary)
📝 Quick Summary: Radical Stability
Order: 3° > 2° > 1° > CH₃•
Reason: Alkyl groups donate electrons by +I effect and hyperconjugation, stabilizing the free radical.
Application: More stable radical = Major product
Conditions Required
| Reagent | Condition |
|---|---|
| Cl₂ | Sunlight (hν) or Heat (Δ) |
| Br₂ | Sunlight (hν) or Heat (Δ) |
Without light, no reaction occurs.
NCERT Points to Remember
- Chlorination and bromination proceed by a free radical chain mechanism
- UV light or heat is essential to generate free radicals
- Homolytic bond cleavage occurs in the initiation step
- Bromination is more selective than chlorination
- Radical stability order: 3° > 2° > 1° > CH₃•
Board PYQs
Answer: Sunlight provides energy for the homolytic cleavage of the Cl–Cl bond, producing chlorine free radicals that initiate the reaction.
Q2. Name the three steps involved in free radical halogenation.
Answer:
- Initiation
- Propagation
- Termination
Q3. Define homolytic cleavage.
Answer: Homolytic cleavage is the equal breaking of a covalent bond such that each atom takes one electron, resulting in the formation of free radicals.
Q4. Why is bromination more selective than chlorination?
Answer: Bromination has a higher activation energy and therefore occurs through the formation of the more stable free radical, making it more selective than chlorination.
- RH + Cl₂ ──hν/Δ──► RCl + HCl
- RH + Br₂ ──hν/Δ──► RBr + HBr
Initiation:
- Cl₂ ──hν──► Cl• + Cl•
Propagation:
- Cl• + CH₄ ─► CH₃• + HCl
- CH₃• + Cl₂ ─► CH₃Cl + Cl•
Termination:
- Cl• + Cl• ─► Cl₂
- CH₃• + Cl• ─► CH₃Cl
- CH₃• + CH₃• ─► C₂H₆
Methane Chlorination Series:
- CH₄ + Cl₂ ──hν──► CH₃Cl + HCl
- CH₃Cl + Cl₂ ──hν──► CH₂Cl₂ + HCl
- CH₂Cl₂ + Cl₂ ──hν──► CHCl₃ + HCl
- CHCl₃ + Cl₂ ──hν──► CCl₄ + HCl
PART 2 (CONTINUED) – PREPARATION FROM ALKENES
Board Weightage: ★★★★★ (One of the most important topics)Introduction
- Alkenes contain a carbon-carbon double bond (C=C)
- The π-bond is weaker than the σ-bond
- Therefore, the π-bond breaks easily
- Halogens or hydrogen halides add across the double bond
- This is called an Addition Reaction
General Reaction
where HX = HCl, HBr, or HI
Why are Alkenes More Reactive?
Double bond ↓ Contains π bond ↓ π bond is weak ↓ Breaks easily ↓ Electrophilic addition occurs
Addition of Hydrogen Halides (HX)
HX may be: HCl, HBr, or HI
Examples:
- Ethene + HCl: CH₂=CH₂ + HCl ──► CH₃CH₂Cl (Chloroethane)
- Ethene + HBr: CH₂=CH₂ + HBr ──► CH₃CH₂Br (Bromoethane)
- Ethene + HI: CH₂=CH₂ + HI ──► CH₃CH₂I (Iodoethane)
Unsymmetrical Alkenes
This is where Markovnikov Rule comes into the picture.
- One carbon: CH₃ (3 H)
- Other carbon: CH₂ (2 H)
- Different → Unsymmetrical
🔴 MARKOVNIKOV RULE ⭐⭐⭐⭐⭐
Most important theory of this chapter.
Definition
When an unsymmetrical reagent (HX) adds to an unsymmetrical alkene:
- Hydrogen goes to the carbon already containing more hydrogen atoms
- Halogen goes to the carbon having fewer hydrogen atoms
"Rich Become Richer"
Hydrogen-rich carbon → Gets another hydrogen
Example: Propene
Hydrogen count:
- CH₃ = 3 H
- CH = 1 H
- CH₂ = 2 H
Carbon with more hydrogen: CH₂
Therefore:
- H goes to CH₂
- Br goes to middle carbon
Mechanism of Markovnikov Addition
Two possibilities:
- Carbocation 1: Primary Carbocation (Unstable)
- Carbocation 2: Secondary Carbocation (More stable)
Reaction proceeds through secondary carbocation.
Step 2: Br⁻ attacks.
Final product: 2-Bromopropane
Why is Markovnikov Product Major?
Because reaction proceeds through the most stable carbocation
3° > 2° > 1° > CH₃⁺
Exactly like free radicals.
📝 Quick Summary: Markovnikov Rule
Rule: "Rich get Richer" - Hydrogen goes to carbon with more H atoms
Mechanism: Carbocation formation → Most stable carbocation forms → Nucleophile attacks
Key Point: Stability determines the product
Another Example: But-1-ene
Board Question
Answer: When an unsymmetrical reagent adds to an unsymmetrical alkene, the negative part attaches to the carbon atom carrying fewer hydrogen atoms, while hydrogen attaches to the carbon atom carrying more hydrogen atoms.
🔴 ANTI-MARKOVNIKOV RULE (PEROXIDE EFFECT) ⭐⭐⭐⭐⭐
Also called Peroxide Effect
Definition
In the presence of Organic Peroxides (ROOR), the addition of HBr takes place opposite to Markovnikov Rule.
Therefore:
- Br attaches to carbon having more hydrogen atoms
Important Condition
- Not with HCl ❌
- Not with HI ❌
Board Favourite Question
Answer: The free radical mechanism is energetically favourable only for HBr. It does not occur with HCl or HI because the reaction steps become energetically unfavourable.
Example: Propene
Comparison
| Condition | Reaction | Product |
|---|---|---|
| Without Peroxide | CH₃CH=CH₂ + HBr | CH₃CHBrCH₃ (2-Bromopropane) |
| With Peroxide | CH₃CH=CH₂ + HBr + ROOR | CH₃CH₂CH₂Br (1-Bromopropane) |
Peroxide → Breaks → Free Radicals → Free Radical Mechanism → Anti-Markovnikov
Why only HBr?
- HCl: Very strong bond → Reaction not favourable
- HBr: Perfect bond strength → Reaction proceeds
- HI: Very weak → Chain reaction not maintained
Hence, only HBr shows peroxide effect.
Mechanism of Peroxide Effect
Three steps (exactly like free radical chlorination):
Initiation
Then: RO• + HBr ──► ROH + Br•
Propagation
Then: CH₃CH•CH₂Br + HBr ──► CH₃CH₂CH₂Br + Br•
Again, Br radical is regenerated.
Termination
or
R• + Br• ──► RBr
Reaction stops.
Addition of Halogens
Very Important
Alkenes react with Cl₂ or Br₂ to form Vicinal Dihalides.
Examples:
- Ethene + Br₂: CH₂=CH₂ + Br₂ ──► CH₂BrCH₂Br (1,2-Dibromoethane)
- Ethene + Cl₂: CH₂=CH₂ + Cl₂ ──► CH₂ClCH₂Cl (1,2-Dichloroethane)
Test for Unsaturation
This reaction is used in laboratory.
- Brown colour
- Alkene added
- Brown colour disappears
Reason: Br₂ is consumed. Hence, presence of double bond.
NCERT Important Notes
- Addition to alkenes is an electrophilic addition reaction
- Markovnikov's rule applies to addition of HX to unsymmetrical alkenes
- Peroxide effect is shown only by HBr
- Addition of Cl₂ or Br₂ forms vicinal dihalides
- Bromine water is decolourised by alkenes because bromine adds across the double bond
Comparison Table
| Feature | Markovnikov | Anti-Markovnikov |
|---|---|---|
| Reagent | HX | HBr + ROOR |
| Mechanism | Carbocation | Free radical |
| Br goes to | Carbon with fewer H | Carbon with more H |
| Major Product (Propene) | 2-Bromopropane | 1-Bromopropane |
| Condition | Normal | Presence of peroxide |
Board PYQs
Answer: When an unsymmetrical reagent (HX) adds to an unsymmetrical alkene, hydrogen attaches to the carbon atom already containing more hydrogen atoms, while the halide attaches to the carbon atom containing fewer hydrogen atoms.
Q2. Why does peroxide effect occur only with HBr?
Answer: The free radical chain mechanism is energetically favourable only for HBr. It is not favourable for HCl or HI.
Q3. What is the major product formed when propene reacts with HBr in the presence of peroxide?
Answer: 1-Bromopropane
Q4. What is formed when ethene reacts with bromine?
Answer: 1,2-Dibromoethane, a vicinal dihalide.
- Mechanism: I – P – T → I Prefer Tea (I = Initiation, P = Propagation, T = Termination)
- Radical Stability: 3 > 2 > 1 > M (Tertiary > Secondary > Primary > Methyl)
- Methane Chlorination Series: CH₄ → CH₃Cl → CH₂Cl₂ → CHCl₃ → CCl₄
- Markovnikov Rule: Rich get Richer (Carbon with more H → Gets another H)
- Peroxide Effect: P = Peroxide = Position Reversed (Normal product becomes reversed)
- Exception: Only HBr (Mnemonic: "Bromine Believes in Peroxide.")
- CH₂=CH₂ + HCl → CH₃CH₂Cl
- CH₂=CH₂ + HBr → CH₃CH₂Br
- CH₂=CH₂ + HI → CH₃CH₂I
- CH₃CH=CH₂ + HBr → CH₃CHBrCH₃ (Markovnikov)
- CH₃CH=CH₂ + HBr + ROOR → CH₃CH₂CH₂Br (Anti-Markovnikov)
- CH₂=CH₂ + Br₂ → CH₂BrCH₂Br
- CH₂=CH₂ + Cl₂ → CH₂ClCH₂Cl
- If you see: HBr + Peroxide (ROOR) → immediately think Anti-Markovnikov
- HCl or HI, even with peroxide → No peroxide effect; use Markovnikov's rule
PART 3 – PREPARATION OF HALOARENES
Board Weightage: ★★★★★ (Very Important)Introduction
Haloarenes cannot be prepared by free radical halogenation like alkanes because:
- The benzene ring is highly stable due to resonance
- Addition reactions would destroy aromaticity
- Therefore, benzene undergoes electrophilic substitution instead of addition
METHOD 1 – DIRECT HALOGENATION OF BENZENE
General Reaction
where X = Cl or Br
This is an Electrophilic Aromatic Substitution (EAS) reaction.
A. Chlorination of Benzene ⭐⭐⭐⭐⭐
Product: Chlorobenzene
Catalyst Used
- FeCl₃
- AlCl₃
Both are Lewis acids.
Role of FeCl₃
FeCl₃ reacts with Cl₂ to generate the electrophile (Cl⁺).
The Cl⁺ ion attacks the benzene ring.
Why is FeCl₃ Needed?
Without FeCl₃
- Cl₂ is not electrophilic enough
- Benzene does not react easily
With FeCl₃
- Cl⁺ is produced
- Reaction becomes fast
Mechanism of Chlorination
Cl₂ + FeCl₃ ──► Cl⁺ + FeCl₄⁻
Step 2 – Attack on Benzene:
The π electrons of benzene attack Cl⁺.
A positively charged intermediate (σ-complex or arenium ion) is formed.
Step 3 – Loss of H⁺:
Hydrogen leaves. Aromaticity is restored.
Final product: Chlorobenzene
EAS = Electrophile → Attacks → Substitution → Not Addition
B. Bromination of Benzene ⭐⭐⭐⭐⭐
Product: Bromobenzene
Catalyst: FeBr₃
Mechanism is exactly the same as chlorination.
C. Iodination of Benzene
Why oxidising agent?
Because HI formed during the reaction reverses the reaction.
Common oxidising agents:
- HNO₃
- HIO₃
They remove HI, shifting the reaction forward.
D. Fluorination
Direct fluorination is not preferred.
Reason:
- Fluorine is extremely reactive
- Reaction becomes violent and difficult to control
- Therefore, fluorobenzene is generally prepared by the Balz–Schiemann reaction
PREPARATION FROM DIAZONIUM SALTS
Very Important for Board Exams
What is a Diazonium Salt?
Example: C₆H₅N₂⁺Cl⁻ (Benzenediazonium chloride)
Preparation of Benzenediazonium Chloride
↓
NaNO₂ + HCl
0–5°C
↓
C₆H₅N₂⁺Cl⁻
- Temperature must be maintained at 0-5°C
- Higher temperatures cause decomposition
🔴 SANDMEYER REACTION ⭐⭐⭐⭐⭐
Definition
The Sandmeyer reaction is used to replace the diazonium group with various halogens using copper salts as catalysts.
General Reaction
Specific Reactions
- Sandmeyer Chlorination: C₆H₅N₂⁺Cl⁻ + CuCl ──► C₆H₅Cl + N₂↑
- Sandmeyer Bromination: C₆H₅N₂⁺Cl⁻ + CuBr ──► C₆H₅Br + N₂↑
- Sandmeyer Cyanation: C₆H₅N₂⁺Cl⁻ + CuCN ──► C₆H₅CN + N₂↑
Mechanism
- Diazonium salt reacts with Cu(I) salt
- Free radical mechanism
- Nitrogen gas is evolved
- Aryl halide is formed
Board Question
Answer: The Sandmeyer reaction is a chemical reaction used to synthesize aryl halides from aryl diazonium salts using copper(I) halides as catalysts.
🔴 GATTERMANN REACTION ⭐⭐⭐⭐
Definition
The Gattermann reaction is similar to the Sandmeyer reaction but uses Cu powder and HX instead of CuX.
General Reaction
Specific Reactions
- Gattermann Chlorination: C₆H₅N₂⁺Cl⁻ + Cu + HCl ──► C₆H₅Cl + N₂↑
- Gattermann Bromination: C₆H₅N₂⁺Cl⁻ + Cu + HBr ──► C₆H₅Br + N₂↑
🔴 BALZ–SCHIEMANN REACTION ⭐⭐⭐⭐⭐
Definition
The Balz–Schiemann reaction is used to prepare aryl fluorides from diazonium salts.
General Reaction
Specific Reaction
Why is this important?
- Direct fluorination of benzene is not possible
- This is the only practical method to prepare fluorobenzene
Board Question
Answer: Fluorobenzene is prepared by the Balz–Schiemann reaction. Benzenediazonium fluoroborate is heated to give fluorobenzene, nitrogen gas, and boron trifluoride.
NCERT Points to Remember
- Diazonium salts are prepared at 0-5°C
- Sandmeyer reaction uses CuX (X = Cl, Br, CN)
- Gattermann reaction uses Cu powder + HX
- Balz–Schiemann reaction is used for fluorination
- All these reactions evolve nitrogen gas
Direct Halogenation:
- C₆H₆ + Cl₂ ──FeCl₃──► C₆H₅Cl + HCl
- C₆H₆ + Br₂ ──FeBr₃──► C₆H₅Br + HBr
- C₆H₆ + I₂ ──HNO₃──► C₆H₅I (oxidising agent required)
Diazonium Salt Preparation:
- C₆H₅NH₂ + NaNO₂ + 2HCl ──0-5°C──► C₆H₅N₂⁺Cl⁻ + NaCl + 2H₂O
Sandmeyer Reaction:
- C₆H₅N₂⁺Cl⁻ + CuCl ──► C₆H₅Cl + N₂↑
- C₆H₅N₂⁺Cl⁻ + CuBr ──► C₆H₅Br + N₂↑
- C₆H₅N₂⁺Cl⁻ + CuCN ──► C₆H₅CN + N₂↑
Gattermann Reaction:
- C₆H₅N₂⁺Cl⁻ + Cu + HCl ──► C₆H₅Cl + N₂↑
- C₆H₅N₂⁺Cl⁻ + Cu + HBr ──► C₆H₅Br + N₂↑
Balz–Schiemann Reaction:
- C₆H₅N₂⁺BF₄⁻ ──Heat──► C₆H₅F + N₂↑ + BF₃
PART 4 – PHYSICAL PROPERTIES
Board Weightage: ★★★☆☆State
- Lower alkanes (C₁-C₄): Gases
- C₅-C₁₀: Liquids
- Higher: Solids
Colour
- Colourless
Odour
- Sweetish characteristic odour
Solubility
- Insoluble in water
- Soluble in organic solvents (ether, alcohol, chloroform)
Boiling Point
- Increases with molecular weight
- For isomeric haloalkanes: 1° < 2° < 3° (due to surface area)
- Order: RI > RBr > RCl > RF (for same alkyl group)
Melting Point
- Generally increases with molecular weight
- Symmetrical molecules have higher melting points
Density
- Most haloalkanes are denser than water
- Order: RI > RBr > RCl > RF
Dipole Moment
- CH₃F > CH₃Cl > CH₃Br > CH₃I (due to electronegativity difference)
Comparison Table
| Compound | State | BP (°C) | MP (°C) | Density (g cm⁻³) |
|---|---|---|---|---|
| CH₃Cl | Gas | -24 | -97 | 0.91 |
| C₂H₅Br | Liquid | 38 | -115 | 1.34 |
| (CH₃)₃CCl | Liquid | 71 | -50 | 1.19 |
Physical Properties of Haloarenes
- Generally liquids (C₆-C₁₀) or solids (higher)
- Higher boiling points than corresponding alkanes due to polarity
| Compound | BP (°C) | MP (°C) | Density (g cm⁻³) |
|---|---|---|---|
| Chlorobenzene | 131 | -45 | 1.11 |
| Bromobenzene | 156 | -73 | 1.50 |
| Iodobenzene | 184 | -84 | 1.93 |
PART 5 – CHEMICAL REACTIONS OF HALOALKANES
Board Weightage: ★★★★★ (Highest weightage)Nucleophilic Substitution Reactions
SN1 Mechanism (Substitution Nucleophilic Unimolecular)
- Occurs with: Tertiary halides (3°)
- Rate depends on: Only substrate concentration (Rate = k[RX])
- Mechanism: Two-step process with carbocation intermediate
- Stereochemistry: Racemisation occurs (50% retention, 50% inversion)
- Solvent: Polar protic solvents favour SN1
SN2 Mechanism (Substitution Nucleophilic Bimolecular)
- Occurs with: Primary (1°) and secondary (2°) halides
- Rate depends on: Both substrate and nucleophile (Rate = k[RX][Nu⁻])
- Mechanism: One-step process with transition state
- Stereochemistry: Inversion of configuration (Walden inversion)
- Solvent: Polar aprotic solvents favour SN2
Comparison: SN1 vs SN2
| Feature | SN1 | SN2 |
|---|---|---|
| Substrate | Tertiary (3°) | Primary (1°), Secondary (2°) |
| Rate Law | Rate = k[RX] | Rate = k[RX][Nu⁻] |
| Mechanism | Two-step (carbocation) | One-step (transition state) |
| Stereochemistry | Racemisation | Inversion |
| Nucleophile strength | Not important | Important |
Stereochemical Aspects of Nucleophilic Substitution
Board Weightage: ★★★★★ (Very Important)Optical Activity
Compounds that rotate the plane of plane-polarised light are called optically active compounds.
- Dextrorotatory (+): Rotates plane to the right (clockwise)
- Laevorotatory (-): Rotates plane to the left (anticlockwise)
Chirality and Enantiomers
Chiral molecules: Molecules that are non-superimposable on their mirror images (like left and right hands).
Achiral molecules: Molecules that are superimposable on their mirror images.
Enantiomers: Stereoisomers that are non-superimposable mirror images of each other.
Racemic mixture: Equal mixture of two enantiomers (optically inactive, denoted as dl or ±).
Asymmetric Carbon (Stereocentre)
A carbon atom attached to four different groups is called asymmetric carbon or stereocentre.
Retention, Inversion and Racemisation
When a bond to an asymmetric carbon is broken during a reaction, three outcomes are possible:
- Retention of configuration: Spatial arrangement remains the same
- Inversion of configuration: Spatial arrangement is inverted (like umbrella turning inside out)
- Racemisation: 50:50 mixture of both configurations (optically inactive)
Stereochemistry of SN1 and SN2 Reactions
SN2 Reactions
- Nucleophile attacks from the side opposite to the leaving group
- Result: Inversion of configuration (Walden inversion)
- Example: (–)-2-bromooctane + NaOH → (+)-octan-2-ol
SN1 Reactions
- Carbocation intermediate is planar (sp² hybridised, achiral)
- Nucleophile can attack from either side
- Result: Racemisation (50:50 mixture of retention and inversion)
- Example: (–)-2-bromobutane + NaOH → (±)-butan-2-ol
📌 Important Board Points:
- SN2 → Inversion of configuration
- SN1 → Racemisation
- Optical activity is due to molecular asymmetry (chirality)
- Enantiomers have identical physical properties except optical rotation
Elimination Reactions
β-Elimination (Dehydrohalogenation)
- Reagent: Alcoholic KOH
- Product: Alkene
Zaitsev Rule
The more substituted alkene is the major product.
Hoffmann Rule
With bulky bases, the less substituted alkene is the major product.
Reactions with Metals
Wurtz Reaction
Fittig Reaction
Wurtz-Fittig Reaction
Organometallic Compounds
Grignard Reagent
- Preparation: Alkyl halide + magnesium in dry ether
- Importance: Used in organic synthesis to form C-C bonds
Reduction
Reducing Agents
- Zn + HCl
- LiAlH₄
- NaBH₄
- H₂/Pd
Nucleophilic Substitution:
- R-Cl + NaOH ──► R-OH + NaCl (SN1/SN2)
- R-Cl + NaCN ──► R-CN + NaCl
- R-Cl + NaNH₂ ──► R-NH₂ + NaCl
- R-Cl + AgNO₂ ──► R-NO₂ + AgCl
Elimination:
- R-CH₂-CH₂-Cl + KOH (alcoholic) ──► R-CH=CH₂ + KCl + H₂O
With Metals:
- 2R-Cl + 2Na ──dry ether──► R-R + 2NaCl (Wurtz)
- 2Ar-Cl + 2Na ──dry ether──► Ar-Ar + 2NaCl (Fittig)
- R-Cl + Ar-Cl + 2Na ──dry ether──► R-Ar + 2NaCl (Wurtz-Fittig)
- R-Cl + Mg ──dry ether──► R-MgCl (Grignard)
Reduction:
- R-Cl + Zn + HCl ──► R-H + ZnCl₂
- R-Cl + LiAlH₄ ──► R-H
- R-Cl + H₂ ──Pd──► R-H + HCl
Complete Nucleophilic Substitution Reactions
Important reagents and their substitution products:
1. With NaOH/KOH (Formation of Alcohol)
Reaction: R-X + NaOH ──► R-OH + NaX
Example: CH₃CH₂Cl + NaOH ──► CH₃CH₂OH + NaCl
Product: Alcohol
2. With H₂O (Formation of Alcohol)
Reaction: R-X + H₂O ──► R-OH + HX
Example: CH₃CH₂Cl + H₂O ──► CH₃CH₂OH + HCl
Product: Alcohol
3. With NaOR′ (Formation of Ether)
Reaction: R-X + NaOR′ ──► R-OR′ + NaX
Example: CH₃CH₂Cl + NaOCH₃ ──► CH₃CH₂OCH₃ + NaCl
Product: Ether
4. With NaI (Formation of Alkyl Iodide)
Reaction: R-X + NaI ──► R-I + NaX
Example: CH₃CH₂Cl + NaI ──► CH₃CH₂I + NaCl
Product: Alkyl iodide
5. With NH₃ (Formation of Primary Amine)
Reaction: R-X + NH₃ ──► R-NH₂ + HX
Example: CH₃CH₂Cl + NH₃ ──► CH₃CH₂NH₂ + HCl
Product: Primary amine
6. With R′NH₂ (Formation of Secondary Amine)
Reaction: R-X + R′NH₂ ──► R-NHR′ + HX
Example: CH₃CH₂Cl + CH₃NH₂ ──► CH₃CH₂NHCH₃ + HCl
Product: Secondary amine
7. With R′R′′NH (Formation of Tertiary Amine)
Reaction: R-X + R′R′′NH ──► R-NR′R′′ + HX
Example: CH₃CH₂Cl + (CH₃)₂NH ──► CH₃CH₂N(CH₃)₂ + HCl
Product: Tertiary amine
8. With KCN (Formation of Nitrile)
Reaction: R-X + KCN ──► R-CN + KX
Example: CH₃CH₂Cl + KCN ──► CH₃CH₂CN + KCl
Product: Nitrile (cyanide)
9. With AgCN (Formation of Isonitrile)
Reaction: R-X + AgCN ──► R-NC + AgX
Example: CH₃CH₂Cl + AgCN ──► CH₃CH₂NC + AgCl
Product: Isonitrile (isocyanide)
Note: AgCN gives isonitrile, KCN gives nitrile
10. With KNO₂ (Formation of Alkyl Nitrite)
Reaction: R-X + KNO₂ ──► R-ONO + KX
Example: CH₃CH₂Cl + KNO₂ ──► CH₃CH₂ONO + KCl
Product: Alkyl nitrite
11. With AgNO₂ (Formation of Nitroalkane)
Reaction: R-X + AgNO₂ ──► R-NO₂ + AgX
Example: CH₃CH₂Cl + AgNO₂ ──► CH₃CH₂NO₂ + AgCl
Product: Nitroalkane
Note: AgNO₂ gives nitroalkane, KNO₂ gives alkyl nitrite
12. With R′COOAg (Formation of Ester)
Reaction: R-X + R′COOAg ──► R′COOR + AgX
Example: CH₃CH₂Cl + CH₃COOAg ──► CH₃COOCH₂CH₃ + AgCl
Product: Ester
13. With LiAlH₄ (Formation of Hydrocarbon)
Reaction: R-X + LiAlH₄ ──► R-H + LiX + AlH₃
Example: CH₃CH₂Cl + LiAlH₄ ──► CH₃CH₃ + LiCl + AlH₃
Product: Hydrocarbon (alkane)
14. With R′-M⁺ (Formation of Alkane - Coupling)
Reaction: R-X + R′-M⁺ ──► R-R′ + M⁺X⁻
Example: CH₃CH₂Cl + CH₃MgBr ──► CH₃CH₂CH₃ + MgBrCl
Product: Alkane (coupling product)
📌 Important Notes:
- AgCN vs KCN: AgCN gives isonitrile (R-NC) while KCN gives nitrile (R-CN)
- AgNO₂ vs KNO₂: AgNO₂ gives nitroalkane (R-NO₂) while KNO₂ gives alkyl nitrite (R-ONO)
- LiAlH₄: Strong reducing agent, converts haloalkanes to alkanes
- Grignard (R-MgX): Acts as a source of R⁻ nucleophile for coupling reactions
- Ammonolysis: Reaction with NH₃ gives primary amine, with secondary amines gives tertiary amines
PART 6 – CHEMICAL REACTIONS OF HALOARENES
Board Weightage: ★★★★☆Why Haloarenes are Less Reactive
Reasons:
- Resonance: The lone pair on halogen participates in resonance with the benzene ring
- Partial double bond character: C-X bond acquires partial double bond character
- sp² carbon: The carbon is sp² hybridized (more electronegative than sp³)
- Bond length: C-X bond in haloarenes is shorter than in haloalkanes
R-S-B (Resonance, sp², Bond length) = Less reactive
Electrophilic Substitution
Haloarenes undergo electrophilic substitution reactions, but more slowly than benzene because halogens withdraw electron density by the -I effect.
Why halogen is ortho/para directing?
Although halogen is electron-withdrawing by inductive effect, it donates electron density to the ring by resonance through its lone pair. This resonance stabilizes the sigma complex formed during attack at ortho and para positions more than at meta position. Thus, haloarenes are deactivated yet ortho/para directing.
NCERT reactions to remember:
- Halogenation: C₆H₅Cl + Cl₂ ──anhyd. FeCl₃──► o-dichlorobenzene + p-dichlorobenzene + HCl
- Nitration: C₆H₅Cl + HNO₃ ──conc. H₂SO₄──► o-nitrochlorobenzene + p-nitrochlorobenzene + H₂O
- Sulphonation: C₆H₅Cl + H₂SO₄ ──heat──► o-chlorobenzenesulphonic acid + p-chlorobenzenesulphonic acid + H₂O
📌 Important Note:
Haloarenes generally do not undergo Friedel-Crafts reaction easily. The ring is deactivated by the halogen and the halogen can also form a complex with Lewis acid catalysts such as AlCl₃.
Nucleophilic Substitution
Haloarenes are less reactive towards nucleophilic substitution.
Reasons for low reactivity:
- Resonance effect: Lone pair on halogen conjugates with benzene ring, giving C-X bond partial double bond character
- Hybridisation difference: Carbon is sp² (more electronegative) in haloarenes vs sp³ in haloalkanes
- Bond length: C-X bond is shorter in haloarenes (169 pm vs 177 pm), harder to break
- Instability of phenyl cation: Phenyl cation is not stabilized by resonance, SN1 ruled out
- Electron repulsion: Nucleophile repelled by electron-rich arene ring
Conditions required:
- High temperature and pressure
- Strong electron-withdrawing groups (NO₂) ortho/para to halogen
Dow's Process (Replacement by hydroxyl group)
Chlorobenzene can be converted to phenol by heating with aqueous NaOH at 623K and 300 atm pressure.
Effect of NO₂ group
The presence of electron-withdrawing NO₂ group at ortho and para positions increases reactivity of haloarenes towards nucleophilic substitution. The NO₂ group withdraws electron density from the ring and stabilizes the carbanion intermediate through resonance. No effect is observed at meta position.
Benzyne Mechanism
Under extreme conditions, elimination-addition occurs via benzyne intermediate.
Reaction with Metals
Haloarenes undergo sodium-metal coupling reactions in dry ether to form larger hydrocarbons.
Wurtz-Fittig Reaction
A mixture of an alkyl halide and an aryl halide reacts with sodium in dry ether to give an alkylarene.
Example: CH₃Cl + C₆H₅Cl + 2Na ──dry ether──► C₆H₅CH₃ + 2NaCl
Fittig Reaction
Two molecules of an aryl halide react with sodium in dry ether to give a biaryl compound.
Example: 2C₆H₅Cl + 2Na ──dry ether──► C₆H₅-C₆H₅ + 2NaCl
📌 Coupling Shortcut:
- Wurtz: alkyl + alkyl → alkane
- Fittig: aryl + aryl → biaryl
- Wurtz-Fittig: alkyl + aryl → alkylarene
Electrophilic Substitution:
- C₆H₅Cl + Cl₂ ──anhyd. FeCl₃──► o-C₆H₄Cl₂ + p-C₆H₄Cl₂ + HCl (Halogenation)
- C₆H₅Cl + HNO₃ ──conc. H₂SO₄──► o-NO₂C₆H₄Cl + p-NO₂C₆H₄Cl + H₂O (Nitration)
- C₆H₅Cl + H₂SO₄ ──heat──► o-HO₃SC₆H₄Cl + p-HO₃SC₆H₄Cl + H₂O (Sulphonation)
Nucleophilic Substitution:
- C₆H₅Cl + NaOH ──623K, 300atm──► C₆H₅OH + NaCl (Dow's process)
With Metals:
- R-X + Ar-X + 2Na ──dry ether──► R-Ar + 2NaX (Wurtz-Fittig)
- 2Ar-X + 2Na ──dry ether──► Ar-Ar + 2NaX (Fittig)
📌 Important Board Points:
- Haloarenes are less reactive than haloalkanes due to resonance and sp² hybridisation
- Halogen is ortho/para directing but deactivating in electrophilic substitution
- NO₂ at ortho/para positions increases reactivity towards nucleophilic substitution
- Electrophilic substitution in haloarenes mainly includes halogenation, nitration and sulphonation
- Dow's process requires extreme conditions (623K, 300 atm)
- Haloarenes react with sodium in dry ether to give Fittig and Wurtz-Fittig coupling products
PART 7 – POLYHALOGEN COMPOUNDS
Board Weightage: ★★★☆☆Chloroform (CHCl₃)
- Preparation: Chlorination of methane or by haloform reaction
- Properties: Sweet-smelling liquid, heavy
- Uses: Previously used as anaesthetic, now limited
- Harmful effects: Carcinogenic, liver damage
Carbon Tetrachloride (CCl₄)
- Preparation: Exhaustive chlorination of methane
- Properties: Colourless liquid, non-flammable
- Uses: Solvent, fire extinguisher (now limited)
- Harmful effects: Liver and kidney damage, ozone depletion
Freons (CCl₂F₂, CCl₃F)
- Preparation: Manufactured via halogen exchange
- Properties: Colourless gases, non-toxic
- Uses: Refrigerants, propellants
- Harmful effects: Ozone-depleting (banned by Montreal Protocol)
DDT (C₁₄H₉Cl₅)
- Preparation: Reaction of chloral with chlorobenzene
- Properties: White crystalline solid
- Uses: Potent insecticide (banned)
- Harmful effects: Bioaccumulation, environmental persistence
Iodoform (CHI₃)
- Preparation: Haloform reaction of methyl ketones with I₂/NaOH
- Properties: Yellow crystalline solid, characteristic odour
- Uses: Antiseptic
- CH₄ + 3Cl₂ ──hν──► CCl₄ + 6HCl
- CH₃COCH₃ + 3I₂ + 4NaOH ──► CHI₃ + CH₃COONa + 3NaI + 3H₂O (Iodoform test)
📚 FINAL REVISION SHEET
• Haloalkane = C-X (X = F,Cl,Br,I). Classification: primary/secondary/tertiary; mono-/di-/poly-.
• SN1 (tert), SN2 (prim/sec), E1/E2 for elimination, Wurtz, Grignard, reduction.
• Preparation: from alcohols (HX), alkanes (radical), alkenes (addition).
• Haloarenes less reactive; prepare via direct halogenation, Sandmeyer, Gattermann, Balz-Schiemann.
• Polyhalogen compounds – chloroform, CCl₄, freons, DDT, iodoform – know preparation & hazards.
Key Reactions to Memorise
From Alcohols:
- ROH + HCl/ZnCl₂ → RCl + H₂O
- ROH + SOCl₂ → RCl + SO₂ + HCl
- 3ROH + PCl₃ → 3RCl + H₃PO₃
From Alkanes:
- RH + Cl₂ ──hν──► RCl + HCl
- Mechanism: Initiation → Propagation → Termination
From Alkenes:
- CH₃CH=CH₂ + HBr → CH₃CHBrCH₃ (Markovnikov)
- CH₃CH=CH₂ + HBr + ROOR → CH₃CH₂CH₂Br (Anti-Markovnikov)
Haloarenes:
- C₆H₆ + Cl₂ ──FeCl₃──► C₆H₅Cl + HCl
- C₆H₅N₂⁺Cl⁻ + CuCl → C₆H₅Cl + N₂↑ (Sandmeyer)
- C₆H₅N₂⁺BF₄⁻ ──Heat──► C₆H₅F + N₂↑ (Balz-Schiemann)
Memory Tricks Summary
- I-P-T: Initiation-Propagation-Termination (Free radical mechanism)
- 3 > 2 > 1 > M: Radical stability order
- Rich get Richer: Markovnikov rule
- Peroxide = Position Reversed: Anti-Markovnikov (only HBr)
- R-S-B: Resonance, sp², Bond length (Haloarenes less reactive)
Board Exam Tips
- Always write balanced chemical equations
- Mention mechanisms for 5-mark questions
- Draw structures clearly
- Remember exceptions (peroxide effect only with HBr)
- Practice numerical problems on physical properties
🔄 IMPORTANT CONVERSIONS (Maximum 2-Step Reactions)
Board Weightage: ★★★★★ (Very Important)Alkane to Alkene
Ethane → Ethene:
- CH₃CH₃ + Cl₂ ──hν──► CH₃CH₂Cl + HCl (Chlorination)
- CH₃CH₂Cl + KOH (alc) ──Δ──► CH₂=CH₂ + KCl + H₂O (β-Elimination)
Alkene to Alkane
Ethene → Ethane:
- CH₂=CH₂ + HBr ──► CH₃CH₂Br
- CH₃CH₂Br + Zn + H⁺ ──► CH₃CH₃ + ZnBr₂ (Reduction)
Direct: CH₂=CH₂ + H₂ ──Ni──► CH₃CH₃
Alcohol to Alkene
Ethanol → Ethene:
- CH₃CH₂OH + PCl₅ ──► CH₃CH₂Cl + POCl₃ + HCl
- CH₃CH₂Cl + KOH (alc) ──Δ──► CH₂=CH₂ + KCl + H₂O
Direct: CH₃CH₂OH ──conc. H₂SO₄, 170°C──► CH₂=CH₂ + H₂O
Alcohol to Alkane
Ethanol → Ethane:
- CH₃CH₂OH + SOCl₂ ──► CH₃CH₂Cl + SO₂ + HCl
- 2CH₃CH₂Cl + 2Na ──dry ether──► CH₃CH₂CH₂CH₃ + 2NaCl (Wurtz)
Alcohol to Haloalkane
Ethanol → Chloroethane: CH₃CH₂OH + HCl/ZnCl₂ ──► CH₃CH₂Cl + H₂O
Ethanol → Bromoethane: CH₃CH₂OH + HBr ──► CH₃CH₂Br + H₂O
Ethanol → Iodoethane: CH₃CH₂OH + PI₃ ──► CH₃CH₂I + H₃PO₃
Haloalkane to Alcohol
Chloroethane → Ethanol: CH₃CH₂Cl + KOH (aq) ──► CH₃CH₂OH + KCl
Haloalkane to Amine
Chloroethane → Ethylamine: CH₃CH₂Cl + NH₃ (excess) ──► CH₃CH₂NH₂ + HCl
Haloalkane to Nitrile
Chloroethane → Ethanenitrile: CH₃CH₂Cl + KCN ──► CH₃CH₂CN + KCl
Nitrile to Amine
Ethanenitrile → Ethylamine: CH₃CH₂CN + 4[H] ──Ni──► CH₃CH₂CH₂NH₂
Haloalkane to Grignard
Chloroethane → Ethylmagnesium chloride: CH₃CH₂Cl + Mg ──dry ether──► CH₃CH₂MgCl
Grignard to Alcohol
Ethylmagnesium chloride → Ethanol: CH₃CH₂MgCl + H₂O ──► CH₃CH₂OH + Mg(OH)Cl
Benzene to Chlorobenzene
C₆H₆ + Cl₂ ──FeCl₃──► C₆H₅Cl + HCl
Chlorobenzene to Phenol
- C₆H₅Cl + NaOH ──623K, 300atm──► C₆H₅ONa + NaCl (Dow's process)
- C₆H₅ONa + HCl ──► C₆H₅OH + NaCl
Aniline to Chlorobenzene (Sandmeyer)
- C₆H₅NH₂ + NaNO₂ + HCl ──0-5°C──► C₆H₅N₂⁺Cl⁻ + 2H₂O
- C₆H₅N₂⁺Cl⁻ + CuCl ──► C₆H₅Cl + N₂↑ + CuCl₂
Aniline to Bromobenzene (Sandmeyer)
- C₆H₅NH₂ + NaNO₂ + HCl ──0-5°C──► C₆H₅N₂⁺Cl⁻ + 2H₂O
- C₆H₅N₂⁺Cl⁻ + CuBr ──► C₆H₅Br + N₂↑ + CuBr₂
Aniline to Fluorobenzene (Balz-Schiemann)
- C₆H₅NH₂ + NaNO₂ + HCl ──0-5°C──► C₆H₅N₂⁺Cl⁻ + 2H₂O
- C₆H₅N₂⁺Cl⁻ + HBF₄ ──► C₆H₅N₂⁺BF₄⁻ ──Δ──► C₆H₅F + N₂↑ + BF₃
Aniline to Iodobenzene
- C₆H₅NH₂ + NaNO₂ + HCl ──0-5°C──► C₆H₅N₂⁺Cl⁻ + 2H₂O
- C₆H₅N₂⁺Cl⁻ + KI ──► C₆H₅I + N₂↑ + KCl
Ethane to Ethanol
- CH₃CH₃ + Cl₂ ──hν──► CH₃CH₂Cl + HCl
- CH₃CH₂Cl + KOH (aq) ──► CH₃CH₂OH + KCl
Ethanol to Ethanoic Acid
- CH₃CH₂OH ──K₂Cr₂O₇/H₂SO₄──► CH₃CHO
- CH₃CHO ──K₂Cr₂O₇/H₂SO₄──► CH₃COOH
Ethene to Ethanol
- CH₂=CH₂ + HBr ──► CH₃CH₂Br
- CH₃CH₂Br + KOH (aq) ──► CH₃CH₂OH + KBr
Direct: CH₂=CH₂ + H₂O ──H⁺──► CH₃CH₂OH
Ethene to 1,2-Dibromoethane
CH₂=CH₂ + Br₂ ──CCl₄──► CH₂BrCH₂Br
1,2-Dibromoethane to Ethyne
CH₂BrCH₂Br + 2KOH (alc) ──Δ──► HC≡CH + 2KBr + 2H₂O
Alkene to Haloalkane
Ethene → Chloroethane: CH₂=CH₂ + HCl ──► CH₃CH₂Cl
Ethene → Bromoethane: CH₂=CH₂ + HBr ──► CH₃CH₂Br
Haloalkane to Alkene
Chloroethane → Ethene: CH₃CH₂Cl + KOH (alc) ──Δ──► CH₂=CH₂ + KCl + H₂O
Haloalkane to Alkane
Chloroethane → Ethane: CH₃CH₂Cl + Zn + H⁺ ──► CH₃CH₃ + ZnCl₂
Benzene to Bromobenzene
C₆H₆ + Br₂ ──FeBr₃──► C₆H₅Br + HBr
Benzene to Iodobenzene
C₆H₆ + I₂ ──HNO₃──► C₆H₅I + HI
Ethanol to Diethyl Ether
2CH₃CH₂OH ──conc. H₂SO₄, 140°C──► CH₃CH₂OCH₂CH₃ + H₂O
Ethanol to Acetaldehyde
CH₃CH₂OH ──K₂Cr₂O₇/H₂SO₄──► CH₃CHO + H₂O
Ethanol to Ethane
- CH₃CH₂OH + PCl₅ ──► CH₃CH₂Cl + POCl₃ + HCl
- CH₃CH₂Cl + 2[H] ──Zn/HCl──► CH₃CH₃ + HCl
Ethyne to Ethene
HC≡CH + H₂ ──Lindlar catalyst──► CH₂=CH₂
Ethyne to Ethane
HC≡CH + 2H₂ ──Ni──► CH₃CH₃
Ethene to Ethyne
- CH₂=CH₂ + Br₂ ──CCl₄──► CH₂BrCH₂Br
- CH₂BrCH₂Br + 2KOH (alc) ──Δ──► HC≡CH + 2KBr + 2H₂O
1-Bromopropane to Propene
CH₃CH₂CH₂Br + KOH (alc) ──Δ──► CH₃CH=CH₂ + KBr + H₂O
2-Bromopropane to Propene
CH₃CHBrCH₃ + KOH (alc) ──Δ──► CH₃CH=CH₂ + KBr + H₂O
Chloroform to Dichloromethane
CHCl₃ + Zn + HCl ──► CH₂Cl₂ + ZnCl₂
Carbon Tetrachloride to Chloroform
CCl₄ + Zn + HCl ──► CHCl₃ + ZnCl₂
Phenol to Chlorobenzene
- C₆H₅OH + PCl₅ ──► C₆H₅Cl + POCl₃ + HCl
Phenol to Bromobenzene
- C₆H₅OH + PBr₃ ──► C₆H₅Br + H₃PO₃
📝 Quick Tips:
- Alkane → Alkene: Chlorination + β-elimination (alcoholic KOH)
- Alkene → Alkane: HX addition + Zn/H⁺ reduction or direct H₂/Ni
- Alcohol → Alkene: Conc. H₂SO₄ at 170°C (direct)
- Haloalkane → Alcohol: Aqueous KOH (SN1/SN2)
- Haloalkane → Alkene: Alcoholic KOH (elimination)
- Sandmeyer: Diazonium + CuX → Aryl halide
- Wurtz: 2R-X + 2Na → R-R
🎯 Best of Luck for Your Exam!
Study hard, stay focused, and ace your chemistry exam!